easiest way to wire LEDs for dual brightness?
easiest way to wire LEDs for dual brightness?
Yeah, I'll draw up a circuit and post it up
Nice one. I've got a lot of spare LED's knocking about now so I can test small circuits and see what works. I've not ordered the rings yet because I still need to do some measuring (and find a spare set of late spec lights). I'm going to convert the existing brake lights to run with the fogs, so I have quad fog lights and quad running/brake rings. That way I get all the "cool" during normal operation and actually functional fog lights that are a bit different.
Proper rough but there you go.
The 12v for the top input and 12v for the coil can come from the brake 12v
If your running day lights then the middle 12v can just be a switched 12v from the car. If it's side lights and/or brakes then you'll need 12v from both circuits with diodes separating them.
Hope it makes sense
Yes mate.
I've had another idea, the rings I want are 12/24V LEDs. I could just use a simple switching circuit to either use or circumvent a 12v to 24V converter. Running lights would then get the full 12v from the normal circuit, brakes would get 24V and be twice as bright.
Forgot to buy diodes, so I'm testing it using an LED as a diode/resistor between circuits. Worked okay:
http://youtu.be/AMAxkv-VEu0
I think I'm going to use this method to switch between 12v and 24v, using a single diode.
Right, next set of questions:
What size diode(s) do I need? I only want to buy 1 24v supply and then wire all 4 lights in parallel either from the 24v circuit or the 12v circuit and use the relay to switch between the two. I'm slightly concerned about drawing too many amps through one diode.
Basically, if I have a relay that does nothing but switch the supply to either the 12v line or the 24v converter, wire both of those supplies up to all 4 lights in parallel then put a pair of diodes on each light to prevent either circuit feeding back (is this necessary if I'm just using a switching relay?).